In Hierarchical Calculus, a derivative is never written without specifying its rank (type / transformation layer) and its degree (how many successive applications). The compact notation is:
where \(r \in \{0,1,2,\dots\}\) is the rank (0: differential, 1: relative, 2: logarithmic, …) and \(n \in \{0,1,2,\dots\}\) is the degree.
Define the iterated logarithm \(\ln^{(r)}\) recursively:
We may use the shorthand hierarchical variable: \[ u_r(x) := \ln^{(r)}(x). \] Similarly on the function side: \[ v_r(f(x)) := \ln^{(r)}(f(x)). \]
Rank \(r\) selects the transformation layer. Intuitively, rank changes the scale on which you measure variation:
Degree \(n\) counts successive applications within the same rank. Degree does not change the rank. You first choose the rank, then you raise the degree by repetition.
The rank-\(r\), degree-1 hierarchical derivative is defined by:
This makes classical calculus appear explicitly as the rank-zero case.
Degree \(n\) means applying the same rank derivative \(n\) times:
In particular, \(D_{r}^{0}\) is the identity operator: \[ D_{r}^{0}f=f. \]
In computations (especially for series expansions), it is often useful to distinguish:
Because \(\ln^{(r)}\) appears explicitly, you must respect positivity constraints. Typical examples:
The rank-1 relative derivative connects directly to the standard derivative:
Hence:
Define the scale operator:
Then the relative derivative can be written compactly as:
For rank 2:
Then:
The general idea is: \(\delta_r\) differentiates with respect to \(\ln^{(r)}(x)\). For practical ranks (0,1,2) we already have explicit forms; higher ranks follow the same principle.
Rank changes the meaning: \(D_0\) measures classical differential change, while \(D_1\) measures relative (log-scale) change.
This grid enforces precision: first fix the rank, then raise the degree by repetition.
Within a fixed rank, raising the degree becomes computable through \(\delta_r\). Define:
For rank \(1\), a practical coefficient sequence is: \[ A_n^{(1)}(x) := \big(D_1^n\,\ln f\big)(x). \] Then:
Early degrees (rank \(1\)):
Similarly for rank \(2\), define \(A_n^{(2)}(x):=\big(D_2^n\,\ln^{(2)}f\big)(x)\) with \(\ln^{(2)}f=\ln(\ln f)\). Then: